Packet N: Bonus 19
A method developed by Benjamin Widom calculates the “excess” form of this quantity for a solute-solvent system obtaining an insertion parameter from adding test particles. For 10 points each:
[10m] Name this quantity, whose differential change is equal to VdP minus SdT in the Gibbs–Duhem equation. This quantity, symbolized mu, is equal to partial molar Gibbs free energy at constant temperature and pressure.
ANSWER: chemical potential [reject “potential”]
[10e] The energy change associated with chemical reactions and these physical phenomena can be calculated using chemical potentials. Discontinuous forms of these phenomena like melting and boiling have latent heats.
ANSWER: phase transitions [or phase changes; accept changes of state; prompt on transitions]
[10h] For higher-order phase transitions, a plot of this quantity versus chemical potential often takes on a lambda shape. A form of this quantity is equal to negative T times the second partial derivative of mu with respect to T.
ANSWER: heat capacity [accept specific heat capacity; accept constant pressure heat capacity or constant volume heat capacity; prompt on C or Cv or Cp]
<Claremont A, Chemistry> | Packet N - Simon Fraser A, Carleton A, Georgia Tech A, Claremont A, Warwick A, Columbia B
| Heard | PPB | E % | M % | H % |
|---|---|---|---|---|
| 10 | 21.00 | 100% | 90% | 20% |
Conversion
| Team | Opponent | Part 1 | Part 2 | Part 3 | Total | Parts |
|---|---|---|---|---|---|---|
| CWRU A | CWRU B | 10 | 10 | 0 | 20 | ME |
| Michigan A | Pittsburgh | 10 | 10 | 0 | 20 | ME |
Summary
| Tournament | Edition | Match | Heard | PPB | E % | M % | H % |
|---|---|---|---|---|---|---|---|
| California (South) | Main Site | ✓ | 1 | 20.00 | 100% | 100% | 0% |
| Canada | Main Site | ✓ | 3 | 23.33 | 100% | 100% | 33% |
| Great Lakes | Main Site | ✓ | 2 | 20.00 | 100% | 100% | 0% |
| UK | Main Site | ✓ | 1 | 20.00 | 100% | 100% | 0% |
| Upper Mid-Atlantic | Main Site | ✓ | 3 | 20.00 | 100% | 67% | 33% |