Round 1: Tossup 7

By the KSS bound, the ratio of eta to entropy density of these substances is lower bounded by one over 4pi. The stress-energy tensor of an ideal one of these substances is rho plus p times a product of 4-velocities plus p times the metric tensor. In the rest frame, a “perfect” one of these substances is parametrized by its isotropic pressure and energy density, and therefore has a diagonal stress-energy tensor. By definition, these substances have zero shear modulus, meaning they cannot undergo shear stress without (10[1])deformation. Many Bose–Einstein condensates act like an idealized (10[1])“super” one of these (-5[1])substances that move without dissipating energy. The Navier–Stokes equations are central (10[1])equations in the “mechanics” (10[1])of, (-5[1])for 10 points, what substances that can flow, including liquids and gases? ■END■ (10[1])

ANSWER: fluids [accept ideal fluids; accept perfect fluids; accept superfluids; accept fluid mechanics; accept Newtonian fluids; prompt on liquids, gases, quark–gluon plasmas, or QGPs by asking “that is a specific example of what more generally defined substances?”] (Eta in the first clue is shear viscosity; the clue refers to the shear viscosity to entropy density ratio.)
<GC, Physics> | Packet A - Brown A, Wisconsin A, Purdue, Maryland B
= Average correct buzzpoint

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Buzzes


Summary

TournamentEditionMatchHeardConv. %Neg %Avg. Buzz
California (North)Main Site3100%67%95.67
California (South)Main Site4100%50%111.75
CanadaMain Site12100%8%103.50
FloridaMain Site3100%0%105.33
Great LakesMain Site5100%40%105.80
Lower Mid-AtlanticMain Site9100%33%111.33
MidwestMain Site888%13%95.71
OverflowMain Site4100%0%99.75
South CentralMain Site2100%0%77.50
SoutheastMain Site7100%14%99.00
UKMain Site12100%17%96.42
Upper Mid-AtlanticMain Site8100%25%104.38
Upstate NYMain Site4100%25%100.00